Problem 1 (25 points)

Write a program to read in 100 numbers and, after you have read 
them all in, print out all the positive numbers you read in.

int main()
{
  int A[100];
  int i;

  for (i=0; i<100; i++)
    {
      cout << "Please give me a number: ";
      cin >> A[i];
    }

  cout << "Here are all the positive numbers read in\n";
  for (i=0; i<100; i++)
  {
    if (A[i] > 0)
      cout << A[i] << endl;
  }

  return 0;
} 

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Problem 2 (25 points):  

A.  Write a function, called find, which takes two strings as 
parameters.  The function will return true if the first character
of the first string appears somewhere in the second string.
Otherwise it will return false.  

bool find(char s[], char t[])
{
  int i;

  for (i=0; t[i] != '\0'; i++)
  {
    if (s[0] == t[i])
      return true;
  }

  return false;
} 

B.  Using the function from part A, write a program that reads in 
a word and prints "yes" if that word begins with a vowel (a,e,i,o,u).
Otherwise it prints "no".

int main()
{ 
  char word[20];
  
  if (find(word,"aeiou"))
    cout << "yes";
  else 
    cout << "no";
}

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Problem 3 (25 points):  

Write a function, called concat, which takes two input streams and 
an output stream as parameters.  Assume all the streams are already 
associated with a file that has been opened.  The two input files 
contain only integers.  The function should make the output file
contain all the integers in the first input file, followed by all
the integers in the second input file. 

void concat(ifstream &in1, ifstream &in2, ofstream &out)
{
  int num;

  in1 >> num
  while (!in1.eof())
  {
    out << num;
    in1 >> num;
  }

  in2 >> num
  while (!in2.eof())
  {
    out << num;
    in2 >> num;
  }
}
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Problem 4 (25 points):  

A.  Write a class called person, which contains a data field
for a first name, a last name, and the year the person was born.
Also include function prototypes, if required, from other parts
of this question.

class person
{
  private:
    char fname[20], lname[20];
    int year_born;
  public:
    int age(int current_year);
};

B.  Write a member function, called age, for the class person.
This function takes the current year as parameter and returns
the age of the person at the end of the year.

int person::age(int current_year)
{
  return current_year - year_born;
}

C. Write a non-member function, called oldest, which takes two 
persons and the current year as input.  The function will return
the oldest person at the end of the year.  
(If they are the same age, return either one) 

person oldest(person p1, person p2, int current_year)
{
  if (p1.age(current_year) > p2.age(current_year))
    return p1;
  else 
    return p2;
}
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