Problem 1 (30 points):  

A.  Write a function called monus that takes two integers as parameters.
The function should return the difference of the first integer minus
the second if the first integer is larger than the second, otherwise
it should return 0.

Solution:

int monus(int x, int y)
{
    if (x > y)
	return x-y;
    else 
	return 0;
}


B.  Using the function of part A, write a program to read in two 
integers and print the difference of the first integer minus the
second if the first integer is larger than the second, otherwise 
print 0.

Solution:

void main()
{
    int num1, num2;
    cout << "Give me two numbers: ";
    cin >> num1 >> num2;
    cout << monus(num1,num2);
}
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Problem 2 (20 points):  

Suppose I have already written a function called regurg that takes
an integer as parameter and returns true if the integer is reguritatable
(a word I just made up), and false otherwise.

Using my function, write a function called regurg_both that takes an 
integer as parameter, and returns true if that integer and twice that integer 
are both regurgitatable, otherwise it returns false.

Solution:

bool regurg_both(int x)
{
    if (regurg(x) && regurg(2*x))
	return true;
    else
	return false;
}

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Problem 3 (20 points):  

Write a function with two integer variables as input parameters.  
The function should check which of its inputs is largest, and set 
both of those integer variables to the largest value of the two.

Solution:

void set_largest(int &x, int &y)
{
    if (x > y)
	y = x;
    else 
	x = y;
}

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Problem 4 (30 points):  

A.  Write a function called print_between that takes two integers
as paramters.  If the first integer is smaller than or equal to the second, 
the function should print out all the integers from the first to the
second, with one space between each integer, and go to a new line
at the end.  If the first integer is larger than the second, an
error message should be printed.

Solution: 

void print_between(int x, int y)
{
    int i;

    if (x <= y)
      {
	for (i = x; i <= y; i++)
	    cout << i << " "
	cout << "\n";
      }
    else
	cout << "Error\n";
}
	

B.  Using the function from part A, write a function called 
print_number_square that prints the following:

1 2 3 4 5
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20
21 22 23 24 25
26 27 28 29 30
31 32 33 34 35
36 37 38 39 40
41 42 43 44 45
46 47 48 49 50
51 52 53 54 55
56 57 58 59 60
61 62 63 64 65
66 67 68 69 70
71 72 73 74 75
76 77 78 79 80
81 82 83 84 85
86 87 88 89 90
91 92 93 94 95
96 97 98 99 100

Solution:

void print_number_square()
{
    int i;
	
    for (i = 1; i < 100; i += 5);
	print_between(i,i+4);
}

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